16t^2+5t=10

Solution for 16t^2+5t=10 equation:

16t^2+5t=10

We move all terms to the left:

16t^2+5t-(10)=0

a = 16; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·16·(-10)
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{665}}{2*16}=\frac{-5-\sqrt{665}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{665}}{2*16}=\frac{-5+\sqrt{665}}{32}
$